What is the derivative of 4x-x^2-3 ?

The derivative of 4x-x^2-3 is -2x+4

What is the first derivative of 4x-x^2-3 ?

The first derivative of 4x-x^2-3 is -2x+4

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\frac{d}{d x} (4 x - x^{2} - 3)

- 2 x + 4

Solution steps

\frac{d}{d x} (4 x - x^{2} - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x) - \frac{d}{d x} (x^{2}) - \frac{d}{d x} (3)

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3) = 0

= 4 - 2 x - 0

Simplify

= - 2 x + 4

y \to 15 lim (y + 3)

\int \frac{sin ( 2 e ^{- 4 x} )}{e ^{4 x}} d x

f (x) = x^{3} - 3 x^{2} + 3 x, g (x) = x

f (3) = 2 x^{2} + 4 x

\int \frac{1}{x ^{2} 25 x ^{2} + 64} d x

What is the derivative of 4x-x^2-3 ?
The derivative of 4x-x^2-3 is -2x+4
What is the first derivative of 4x-x^2-3 ?
The first derivative of 4x-x^2-3 is -2x+4