What is inverse oflaplace 3/(s+5) ?

The answer to inverse oflaplace 3/(s+5) is 3e^{-5t}

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inverse oflaplace 3/(s+5)

inverse laplace

\frac{3}{s + 5}

3 e^{- 5 t}

Solution steps

L^{- 1} {\frac{3}{s + 5}}

= L^{- 1} {3 \cdot \frac{1}{s + 5}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 3 L^{- 1} {\frac{1}{s + 5}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s + 5}} = e^{- 5 t}

= 3 e^{- 5 t}

f (x) = ln (e^{4})

\int \frac{( 6 x ^{3} + 6 x )}{x ^{2} + 1} d x

\frac{d y}{d x} + 3 y = 6

\int e^{- x} (x - 1) d x

\frac{d}{d x} (\frac{x + 2}{10 - 3 x})

What is inverse oflaplace 3/(s+5) ?
The answer to inverse oflaplace 3/(s+5) is 3e^{-5t}