What is the derivative of 8e^{2x} ?

The derivative of 8e^{2x} is 16e^{2x}

What is the first derivative of 8e^{2x} ?

The first derivative of 8e^{2x} is 16e^{2x}

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derivative of

8 e^{2 x}

16 e^{2 x}

Solution steps

\frac{d}{d x} (8 e^{2 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (e^{2 x})

Apply the chain rule:

e^{2 x} \frac{d}{d x} (2 x)

= e^{2 x} \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= 8 e^{2 x} \cdot 2

Simplify

= 16 e^{2 x}

\int e^{- x} - e^{x} d x

y^{^{''}} + 11 y = 0

x^{2} = 2 y

y = 9 x, y = \frac{3}{7} x, y = 52 - x^{2}

f (x) = \frac{x}{x ^{2} + 25}

What is the derivative of 8e^{2x} ?
The derivative of 8e^{2x} is 16e^{2x}
What is the first derivative of 8e^{2x} ?
The first derivative of 8e^{2x} is 16e^{2x}