What is the integral of-tsqrt(z) ?

The integral of-tsqrt(z) is -(sqrt(z)t^2)/2+C

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integral of-tsqrt(z)

\int - t z d t

- \frac{z t ^{2}}{2} + C

Solution steps

\int - t z d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - z \cdot \int t d t

Apply the Power Rule

: \frac{t ^{2}}{2}

= - z \frac{t ^{2}}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{z t ^{2}}{2}

Add a constant to the solution

= - \frac{z t ^{2}}{2} + C

e^{2 x} y^{^{'}} - 2 e^{2 x} y = 3 e^{4 x}

x \to 5 - lim (\frac{12}{5 - x})

\int - 4 sin (3 x) + 6 sin (8 x) d x

\frac{d}{d x} (e^{x} (8 x^{2} - 16 x + 16))

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What is the integral of-tsqrt(z) ?
The integral of-tsqrt(z) is -(sqrt(z)t^2)/2+C