What is the derivative of f(x)=(x^2)/(x-9) ?

The derivative of f(x)=(x^2)/(x-9) is (x^2-18x)/((x-9)^2)

What is the first derivative of f(x)=(x^2)/(x-9) ?

The first derivative of f(x)=(x^2)/(x-9) is (x^2-18x)/((x-9)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = \frac{x ^{2}}{x - 9}

\frac{x ^{2} - 18 x}{( x - 9 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2}}{x - 9})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} ) ( x - 9 ) - \frac{d}{d x} ( x - 9 ) x ^{2}}{( x - 9 ) ^{2}}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (x - 9) = 1

= \frac{2 x ( x - 9 ) - 1 \cdot x ^{2}}{( x - 9 ) ^{2}}

Simplify

\frac{2 x ( x - 9 ) - 1 \cdot x ^{2}}{( x - 9 ) ^{2}} : \frac{x ^{2} - 18 x}{( x - 9 ) ^{2}}

= \frac{x ^{2} - 18 x}{( x - 9 ) ^{2}}

\int_{0}^{2} x + 2 d x

x \to 0 lim (\frac{x}{( x + 0 )})

(4 x^{3} + 5 x^{2})^{5}

f^{^{''}} (x) = x^{2}

f (x) = \frac{7}{x ^{9}}

What is the derivative of f(x)=(x^2)/(x-9) ?
The derivative of f(x)=(x^2)/(x-9) is (x^2-18x)/((x-9)^2)
What is the first derivative of f(x)=(x^2)/(x-9) ?
The first derivative of f(x)=(x^2)/(x-9) is (x^2-18x)/((x-9)^2)