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Popular >

integral of 1/(x(x+0))

Solution

\int \frac{1}{x ( x + 0 )} d x

Solution

- \frac{1}{x} + C

Solution steps

\int \frac{1}{x ( x + 0 )} d x

x (x + 0) = x^{2}

= \int \frac{1}{x ^{2}} d x

Apply the Power Rule

: - \frac{1}{x}

= - \frac{1}{x}

Add a constant to the solution

= - \frac{1}{x} + C

Popular Examples

d/(dθ)(6/(2-3sin(θ)))

\frac{d}{d θ} (\frac{6}{2 - 3 sin ( θ )})

2 y^{^{''}} + y = 0

integral of ((ln^2(x))/(x^{5/3)})

\int (\frac{ln ^{2} ( x )}{x ^{\frac{5}{3}}}) d x

derivative of e^2x derivative of

e^{2} x

integral of sin^3(x/6)

\int sin^{3} (\frac{x}{6}) d x

Frequently Asked Questions (FAQ)

What is the integral of 1/(x(x+0)) ?
The integral of 1/(x(x+0)) is -1/x+C