What is the solution for y^'=(pi*x+y+pi^2)^2 ?

The solution for y^'=(pi*x+y+pi^2)^2 is y=tan(sqrt(pi)(x+c_{1}))sqrt(pi)-pix-pi^2

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y^'=(pi*x+y+pi^2)^2

y^{^{'}} = (π \cdot x + y + π^{2})^{2}

y = tan (π (x + c_{1})) π - π x - π^{2}

Solution steps

y^{'} (x) = (π \cdot x + y + π^{2})^{2}

Solve using substitution:

y = tan (π (x + c_{1})) π - π x - π^{2}

y = tan (π (x + c_{1})) π - π x - π^{2}

\int ln (3 x^{2}) d x

\int sin^{4} (b)

12 x e^{x}

\int \frac{x ^{2} - 7}{x ^{8}} d x

x \to 0 + lim (x^{2} ln (x^{2}))

What is the solution for y^'=(pi*x+y+pi^2)^2 ?
The solution for y^'=(pi*x+y+pi^2)^2 is y=tan(sqrt(pi)(x+c_{1}))sqrt(pi)-pix-pi^2