What is the derivative of x^2+7x-5 ?

The derivative of x^2+7x-5 is 2x+7

What is the first derivative of x^2+7x-5 ?

The first derivative of x^2+7x-5 is 2x+7

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derivative of

x^{2} + 7 x - 5

2 x + 7

Solution steps

\frac{d}{d x} (x^{2} + 7 x - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (7 x) - \frac{d}{d x} (5)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (7 x) = 7

\frac{d}{d x} (5) = 0

= 2 x + 7 - 0

Simplify

= 2 x + 7

\int (\frac{3}{x} - \frac{x x}{4}) d x

z^{^{'}}

\frac{d}{d x} (y^{2} + x^{2})

x^{2} (\frac{d y}{d x}) = y - x y

y = 4 - x^{2}, (1, 2)

What is the derivative of x^2+7x-5 ?
The derivative of x^2+7x-5 is 2x+7
What is the first derivative of x^2+7x-5 ?
The first derivative of x^2+7x-5 is 2x+7