What is the derivative of 2x^2y+4 ?

The derivative of 2x^2y+4 is 2(x^2(dy)/(dx)+2xy)

What is the first derivative of 2x^2y+4 ?

The first derivative of 2x^2y+4 is 2(x^2(dy)/(dx)+2xy)

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\frac{d}{d x} (2 x^{2} y + 4)

2 (x^{2} \frac{d y}{d x} + 2 x y)

Solution steps

\frac{d}{d x} (2 x^{2} y + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2} y) + \frac{d}{d x} (4)

\frac{d}{d x} (2 x^{2} y) = 2 (2 x y + \frac{d y}{d x} x^{2})

\frac{d}{d x} (4) = 0

= 2 (2 x y + \frac{d y}{d x} x^{2}) + 0

Simplify

= 2 (x^{2} \frac{d y}{d x} + 2 x y)

\frac{d}{d x} (\frac{x ^{2} - 3 x - 4}{x - 2})

x \to \infty lim (x + \frac{1}{2})

\frac{\partial}{\partial x} (2 x y + 2 y - x^{2} - 2 y^{2})

\frac{d}{d x} (1 + \frac{x}{1 - x ^{2}})

\int \frac{2 x}{x} d x

What is the derivative of 2x^2y+4 ?
The derivative of 2x^2y+4 is 2(x^2(dy)/(dx)+2xy)
What is the first derivative of 2x^2y+4 ?
The first derivative of 2x^2y+4 is 2(x^2(dy)/(dx)+2xy)