What is the integral of e^x-2cos(x) ?

The integral of e^x-2cos(x) is e^x-2sin(x)+C

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integral of e^x-2cos(x)

\int e^{x} - 2 cos (x) d x

e^{x} - 2 sin (x) + C

Solution steps

\int e^{x} - 2 cos (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int e^{x} d x - \int 2 cos (x) d x

\int e^{x} d x = e^{x}

\int 2 cos (x) d x = 2 sin (x)

= e^{x} - 2 sin (x)

Add a constant to the solution

= e^{x} - 2 sin (x) + C

y = ln (7 - 9 x^{2} + 8 x^{4}), at x = 1

y = x^{2} + 3, (- 3, 12)

n = 1 \sum \infty \frac{1}{( - 3 ) ^{n}}

\frac{d}{d x} (\frac{2 x ^{2} + 4 x + 8}{x})

\int x (e^{x^{2}}) d x

What is the integral of e^x-2cos(x) ?
The integral of e^x-2cos(x) is e^x-2sin(x)+C