What is the tangent of 3/(x^2) ?

The tangent of 3/(x^2) is y=-6/(a_{0)^3}x+9/(a_{0)^2}

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tangent of 3/(x^2)

tangent of

\frac{3}{x ^{2}}

y = - \frac{6}{a _{0}^{3}} x + \frac{9}{a _{0}^{2}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{3}{a _{0}^{2}})

Find the slope of

y = \frac{3}{x ^{2}} : \frac{d y}{d x} = - \frac{6}{x ^{3}}

Compute the slope of

y = \frac{3}{x ^{2}}

x = a_{0} : m = - \frac{6}{a _{0}^{3}}

Find the line with slope m=

- \frac{6}{a _{0}^{3}}

and passing through

(a_{0}, \frac{3}{a _{0}^{2}}) : y = - \frac{6}{a _{0}^{3}} x + \frac{9}{a _{0}^{2}}

y = - \frac{6}{a _{0}^{3}} x + \frac{9}{a _{0}^{2}}

\int \frac{1}{x ^{2} x ^{2} + 9} d x

x \to 3 lim (7 x + ∣ x - 3 ∣)

\frac{\partial}{\partial x} (e^{y} + x e^{x y})

x^{3} f (x)

\int_{3}^{6} 4 d x

What is the tangent of 3/(x^2) ?
The tangent of 3/(x^2) is y=-6/(a_{0)^3}x+9/(a_{0)^2}