What is taylor sin(x)+cos(x) ?

The answer to taylor sin(x)+cos(x) is 1+x-1/2 x^2-1/6 x^3+1/24 x^4+\ldots

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

taylor sin(x)+cos(x)

taylor

sin (x) + cos (x)

1 + x - \frac{1}{2} x^{2} - \frac{1}{6} x^{3} + \frac{1}{24} x^{4} + \dots

Solution steps

Apply the Taylor Formula

= 1 + \frac{\frac{d}{d x} ( sin ( x ) + cos ( x ) ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( sin ( x ) + cos ( x ) ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( sin ( x ) + cos ( x ) ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 1 + \frac{1}{1 !} x + \frac{- 1}{2 !} x^{2} + \frac{- 1}{3 !} x^{3} + \frac{1}{4 !} x^{4} + \dots

Refine

= 1 + x - \frac{1}{2} x^{2} - \frac{1}{6} x^{3} + \frac{1}{24} x^{4} + \dots

y^{^{''}} + 4 y^{^{'}} + 3 y = x

f (x) = x + 5, at x = 11

3 x - 5

\int \frac{1}{x} e^{- x} d x

\frac{d}{d x} (4 x^{3} e^{2 x})

What is taylor sin(x)+cos(x) ?
The answer to taylor sin(x)+cos(x) is 1+x-1/2 x^2-1/6 x^3+1/24 x^4+\ldots