Solution
Solution
Solution steps
Apply the chain rule:
Popular Examples
t^2y^{''}-2ty^'+2y=tln(t)tangent of x^2+xy+y^2=7,(2,1)tangent of derivative of 4x^5-3x^m+2x^n+5x^2-x-6(\partial)/(\partial x)(3y^2+12xy)y^'=3y^2e^x-2y
Frequently Asked Questions (FAQ)
What is the derivative of sin^2(mx+ny(x)) ?
The derivative of sin^2(mx+ny(x)) is 2sin(mx+n{y}(x))cos(mx+n{y}(x))(m+n derivative of {y}(x))What is the first derivative of sin^2(mx+ny(x)) ?
The first derivative of sin^2(mx+ny(x)) is 2sin(mx+n{y}(x))cos(mx+n{y}(x))(m+n derivative of {y}(x))