What is the solution for csc(y)dx+sec(x)dy=0 ?

The solution for csc(y)dx+sec(x)dy=0 is y=arccos(sin(x)-c_{1})+2pin,y=-arccos(sin(x)-c_{1})+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

csc(y)dx+sec(x)dy=0

csc (y) d x + sec (x) d y = 0

y = arccos (sin (x) - c_{1}) + 2 πn, y = - arccos (sin (x) - c_{1}) + 2 πn

Solution steps

csc (y) d x + sec (x) d y = 0

Solve separable ODE:

y = arccos (sin (x) - c_{1}) + 2 πn, y = - arccos (sin (x) - c_{1}) + 2 πn

y = arccos (sin (x) - c_{1}) + 2 πn, y = - arccos (sin (x) - c_{1}) + 2 πn

f (x) = e^{2 x} arcsin (x)

\frac{d}{d x} (10 - x^{2})

y = x^{3} - 9 x

\int x^{2} 5 + x d x

\frac{d y}{d x} = - 9 y

What is the solution for csc(y)dx+sec(x)dy=0 ?
The solution for csc(y)dx+sec(x)dy=0 is y=arccos(sin(x)-c_{1})+2pin,y=-arccos(sin(x)-c_{1})+2pin