What is the derivative of y=2x^2-9x+10 ?

The derivative of y=2x^2-9x+10 is 4x-9

What is the first derivative of y=2x^2-9x+10 ?

The first derivative of y=2x^2-9x+10 is 4x-9

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derivative of

y = 2 x^{2} - 9 x + 10

4 x - 9

Solution steps

\frac{d}{d x} (2 x^{2} - 9 x + 10)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (9 x) + \frac{d}{d x} (10)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (9 x) = 9

\frac{d}{d x} (10) = 0

= 4 x - 9 + 0

Simplify

= 4 x - 9

\frac{d}{d x} (17.5 (x + 1)^{0.75})

k = 1 \sum \infty 8 (\frac{1}{5})^{k}

sin (x) cos (x)

\frac{8 x}{( x ^{2} + 1 )}

x \to 0 - lim (ln (x))

What is the derivative of y=2x^2-9x+10 ?
The derivative of y=2x^2-9x+10 is 4x-9
What is the first derivative of y=2x^2-9x+10 ?
The first derivative of y=2x^2-9x+10 is 4x-9