What is (\partial)/(\partial x)(e^{3x}cos(6y)) ?

The answer to (\partial)/(\partial x)(e^{3x}cos(6y)) is cos(6y)e^{3x}*3

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(\partial)/(\partial x)(e^{3x}cos(6y))

\frac{\partial}{\partial x} (e^{3 x} cos (6 y))

cos (6 y) e^{3 x} \cdot 3

Solution steps

\frac{\partial}{\partial x} (e^{3 x} cos (6 y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= cos (6 y) \frac{\partial}{\partial x} (e^{3 x})

Apply the chain rule:

e^{3 x} \frac{\partial}{\partial x} (3 x)

= e^{3 x} \frac{\partial}{\partial x} (3 x)

\frac{\partial}{\partial x} (3 x) = 3

= cos (6 y) e^{3 x} \cdot 3

\frac{d x}{d t} = 2 + \frac{x}{20}

y = 5 x - 15

\frac{d}{d x} (- \frac{3}{16 ( 1 + x ) ^{\frac{7}{4}}})

\int 4 e^{x} 4 + e^{x} d x

\frac{d}{d x} ((2 x + 1)^{6})

What is (\partial)/(\partial x)(e^{3x}cos(6y)) ?
The answer to (\partial)/(\partial x)(e^{3x}cos(6y)) is cos(6y)e^{3x}*3