What is area f(x)=2sin(x)+sin(2x),y=0,0<= x<= pi ?

The answer to area f(x)=2sin(x)+sin(2x),y=0,0<= x<= pi is 4

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area f(x)=2sin(x)+sin(2x),y=0,0<= x<= pi

area

f (x) = 2 sin (x) + sin (2 x), y = 0, 0 \leq x \leq π

4

Solution steps

Apply the area formula:

\int_{0}^{π} ∣ 2 sin (x) + sin (2 x) ∣ d x

Solve

\int_{0}^{π} ∣ 2 sin (x) + sin (2 x) ∣ d x : 4

The area is:

= 4

x^{^{'}} = x - 15

\frac{d}{d x} (\frac{2}{( 2 + x ) ^{3}})

\frac{d ^{3}}{d x ^{3}} (\frac{4}{x})

\frac{\partial}{\partial y} (e^{2 x} sin (y))

- 4 + 2 e^{x} - 3 x

What is area f(x)=2sin(x)+sin(2x),y=0,0<= x<= pi ?
The answer to area f(x)=2sin(x)+sin(2x),y=0,0<= x<= pi is 4