What is the solution for y^{'''}-9y^{''}+20y^'=0 ?

The solution for y^{'''}-9y^{''}+20y^'=0 is y=c_{1}+c_{2}e^{4t}+c_{3}e^{5t}

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y^{'''}-9y^{''}+20y^'=0

y^{^{'''}} - 9 y^{^{''}} + 20 y^{^{'}} = 0

y = c_{1} + c_{2} e^{4 t} + c_{3} e^{5 t}

Solution steps

y^{'''} (t) - 9 y^{''} (t) + 20 y^{'} (t) = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{4 t} + c_{3} e^{5 t}

y = c_{1} + c_{2} e^{4 t} + c_{3} e^{5 t}

\frac{\partial}{\partial x} (\frac{( x + y )}{x y - 1})

\int_{15}^{30} 9 d x

\frac{d}{d x} (\frac{x}{x ^{2} + 36})

\int_{- 1}^{2} (9 - x^{2}) - (x + 1) d x

\frac{d}{d x} (x^{n + 1})

What is the solution for y^{'''}-9y^{''}+20y^'=0 ?
The solution for y^{'''}-9y^{''}+20y^'=0 is y=c_{1}+c_{2}e^{4t}+c_{3}e^{5t}