What is the solution for y^'=4y(1-y/4) ?

The solution for y^'=4y(1-y/4) is y=-(4e^{4t+4c_{1}})/(1-e^{4(t+c_{1))}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=4y(1-y/4)

y^{^{'}} = 4 y (1 - \frac{y}{4})

y = - \frac{4 e ^{4 t + 4 c_{1}}}{1 - e ^{4 (t + c_{1})}}

Solution steps

y^{'} (t) = 4 y (1 - \frac{y}{4})

Solve separable ODE:

y = - \frac{4 e ^{4 t + 4 c_{1}}}{1 - e ^{4 (t + c_{1})}}

y = - \frac{4 e ^{4 t + 4 c_{1}}}{1 - e ^{4 (t + c_{1})}}

x \to 0 lim (- \frac{4}{x ^{2}})

\frac{x ^{3} - 5 x ^{2} + 1}{x ^{2}}

\int_{0}^{\frac{1}{2}} 5 arcsin (2 y) d y

\int \frac{1}{x ^{2} x ^{2} - 100} d x

f (x) = \frac{sec ( x )}{8 + sec ( x )}

What is the solution for y^'=4y(1-y/4) ?
The solution for y^'=4y(1-y/4) is y=-(4e^{4t+4c_{1}})/(1-e^{4(t+c_{1))}}