What is the derivative of 2x^2e^x ?

The derivative of 2x^2e^x is 2(2xe^x+e^xx^2)

What is the first derivative of 2x^2e^x ?

The first derivative of 2x^2e^x is 2(2xe^x+e^xx^2)

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derivative of

2 x^{2} e^{x}

2 (2 x e^{x} + e^{x} x^{2})

Solution steps

\frac{d}{d x} (2 x^{2} e^{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x^{2} e^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = e^{x}

= 2 (\frac{d}{d x} (x^{2}) e^{x} + \frac{d}{d x} (e^{x}) x^{2})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (e^{x}) = e^{x}

= 2 (2 x e^{x} + e^{x} x^{2})

f (x) = \frac{3}{4 x ^{5}}

\frac{d}{d x} (4 x^{8} + 3 e^{7 x})

x \to 3 lim (x^{2} + x)

y = ln (x^{2} + 5)

What is the derivative of 2x^2e^x ?
The derivative of 2x^2e^x is 2(2xe^x+e^xx^2)
What is the first derivative of 2x^2e^x ?
The first derivative of 2x^2e^x is 2(2xe^x+e^xx^2)