What is the integral from 0 to pi/4 of sec^2(x) ?

The integral from 0 to pi/4 of sec^2(x) is 1

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integral from 0 to pi/4 of sec^2(x)

\int_{0}^{\frac{π}{4}} sec^{2} (x) d x

1

Solution steps

\int_{0}^{\frac{π}{4}} sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= [tan (x)]_{0}^{\frac{π}{4}}

Compute the boundaries:

1

= 1

\frac{d}{d s} (ln (s + \frac{s ^{2} + 4}{2}) 2)

\frac{d}{d x} (2^{\frac{x}{3}})

4 x + 20

f (x) = \frac{x + 3}{2 x + 1}, at x = - 1

2 x^{- \frac{1}{4}}

What is the integral from 0 to pi/4 of sec^2(x) ?
The integral from 0 to pi/4 of sec^2(x) is 1