What is the solution for y^'-y/x =(sqrt(xy))/x ?

The solution for y^'-y/x =(sqrt(xy))/x is y= 1/4 xln^2(x)+c_{1}xln(x)+c_{1}^2x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'-y/x =(sqrt(xy))/x

y^{^{'}} - \frac{y}{x} = \frac{x y}{x}

y = \frac{1}{4} x ln^{2} (x) + c_{1} x ln (x) + c_{1}^{2} x

Solution steps

y^{'} (x) - \frac{y}{x} = \frac{x y}{x}

Solve Bernoulli ODE:

y = \frac{1}{4} x ln^{2} (x) + c_{1} x ln (x) + c_{1}^{2} x

y = \frac{1}{4} x ln^{2} (x) + c_{1} x ln (x) + c_{1}^{2} x

\frac{d x}{d t} = x + \frac{t ^{2}}{2}, x (0) = 0

\frac{d}{d x} (\frac{1}{x ^{10}})

f (x) = \frac{5 x}{x - 3}, at (4)

\int \frac{2 + x + x}{x} d x

\int_{0}^{1} x e^{7 x} d x

What is the solution for y^'-y/x =(sqrt(xy))/x ?
The solution for y^'-y/x =(sqrt(xy))/x is y= 1/4 xln^2(x)+c_{1}xln(x)+c_{1}^2x