What is inverse oflaplace-2*e^{-ln(2)*s} ?

The answer to inverse oflaplace-2*e^{-ln(2)*s} is -2\delta(t-ln(2))

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inverse oflaplace-2e^{-ln(2)s}

inverse laplace

- 2 \cdot e^{- l n (2) \cdot s}

- 2 δ (t - ln (2))

Solution steps

L^{- 1} {- 2 e^{- l n (2) s}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= - 2 L^{- 1} {e^{- l n (2) s}}

L^{- 1} {e^{- l n (2) s}} : δ (t - ln (2))

= - 2 δ (t - ln (2))

\frac{\partial}{\partial y} (4 x y)

\frac{d}{d x} (\frac{1}{3 + x ^{2}})

\int \frac{1}{x + 1 + x - 1} d x

\int \frac{4}{( 4 + x ^{2} ) ^{2}} d x

f (x) = x^{2} + 7, (- 4, 23)

What is inverse oflaplace-2*e^{-ln(2)*s} ?
The answer to inverse oflaplace-2*e^{-ln(2)*s} is -2\delta(t-ln(2))