What is the integral of (e^{2x})/(e^{2x)+2} ?

The integral of (e^{2x})/(e^{2x)+2} is 1/2 ln|e^{2x}+2|+C

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integral of (e^{2x})/(e^{2x)+2}

\int \frac{e ^{2 x}}{e ^{2 x} + 2} d x

\frac{1}{2} ln e^{2 x} + 2 + C

Solution steps

\int \frac{e ^{2 x}}{e ^{2 x} + 2} d x

Apply u-substitution

: \int \frac{1}{2 u} d u

= \int \frac{1}{2 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= \frac{1}{2} ln ∣ u ∣

Substitute back

u = e^{2 x} + 2

= \frac{1}{2} ln e^{2 x} + 2

Add a constant to the solution

= \frac{1}{2} ln e^{2 x} + 2 + C

\frac{d}{d x} (ln (\frac{1}{x - y}))

\int \frac{2 x + 11}{x ^{2} + x - 6} d x

\int \frac{1}{x ^{2}} cos (\frac{1}{x}) d x

\frac{d}{d x} (\frac{x ^{2}}{x ^{2} - 2})

\frac{\partial}{\partial x} ((6 - x - y)^{2})

What is the integral of (e^{2x})/(e^{2x)+2} ?
The integral of (e^{2x})/(e^{2x)+2} is 1/2 ln|e^{2x}+2|+C