What is the limit as x approaches-1+of (3x-5)/(x+1) ?

The limit as x approaches-1+of (3x-5)/(x+1) is -infinity

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limit as x approaches-1+of (3x-5)/(x+1)

x \to - 1 + lim (\frac{3 x - 5}{x + 1})

- \infty

Solution steps

x \to - 1 + lim (\frac{3 x - 5}{x + 1})

\frac{3 x - 5}{x + 1} = (3 x - 5) \frac{1}{x + 1}

= x \to - 1 + lim ((3 x - 5) \frac{1}{x + 1})

x \to a lim [f (x) \cdot g (x)] = x \to a lim f (x) \cdot x \to a lim g (x)

With the exception of indeterminate form

= x \to - 1 + lim (3 x - 5) \cdot x \to - 1 + lim (\frac{1}{x + 1})

x \to - 1 + lim (3 x - 5) = - 8

x \to - 1 + lim (\frac{1}{x + 1}) = \infty

= (- 8) \cdot \infty

Apply Infinity Property:

- c \cdot \infty = - \infty

= - \infty

- \frac{3}{x}

(arctan (cos (x)))^{^{'}}

y^{^{''}} - y^{^{'}} - 6 y = 20 e^{- 2 x}

\frac{\partial}{\partial x} (8 x y^{5} + x^{8} y^{2})

2 y^{^{'''}} + 3 y^{^{''}} - 8 y^{^{'}} + 3 y = 0

What is the limit as x approaches-1+of (3x-5)/(x+1) ?
The limit as x approaches-1+of (3x-5)/(x+1) is -infinity