What is the first derivative of 2x^2 ?

The first derivative of 2x^2 is 4x

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derivative of 2x^2

derivative of

2 x^{2}

4 x

Solution steps

\frac{d}{d x} (2 x^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 2 x^{2 - 1}

Simplify

= 4 x

f (x) = \frac{3}{5} x^{10}

\frac{d}{d x} \frac{( x ^{2} - 4 ) ^{3}}{6}

\int \frac{1}{y ( y + 1 )} d y

y^{^{'}} = 2 t y (1 - y)

x, 0, 0.085