What is the integral of+e^{8x}cos(3x) ?

The integral of+e^{8x}cos(3x) is (3e^{8x}sin(3x))/(73)+(8e^{8x}cos(3x))/(73)+C

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integral of+e^{8x}cos(3x)

\int + e^{8 x} cos (3 x) d x

\frac{3 e ^{8 x} sin ( 3 x )}{73} + \frac{8 e ^{8 x} cos ( 3 x )}{73} + C

Solution steps

\int e^{8 x} cos (3 x) d x

Apply Integration By Parts

: \frac{1}{3} e^{8 x} sin (3 x) - \int \frac{8}{3} e^{8 x} sin (3 x) d x

= \frac{1}{3} e^{8 x} sin (3 x) - \int \frac{8}{3} e^{8 x} sin (3 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} e^{8 x} sin (3 x) - \frac{8}{3} \cdot \int e^{8 x} sin (3 x) d x

Apply Integration By Parts

: - \frac{1}{3} e^{8 x} cos (3 x) - \int - \frac{8}{3} e^{8 x} cos (3 x) d x

= \frac{1}{3} e^{8 x} sin (3 x) - \frac{8}{3} (- \frac{1}{3} e^{8 x} cos (3 x) - \int - \frac{8}{3} e^{8 x} cos (3 x) d x)

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} e^{8 x} sin (3 x) - \frac{8}{3} (- \frac{1}{3} e^{8 x} cos (3 x) - (- \frac{8}{3} \cdot \int e^{8 x} cos (3 x) d x))

Therefore

\int e^{8 x} cos (3 x) d x = \frac{1}{3} e^{8 x} sin (3 x) - \frac{8}{3} (- \frac{1}{3} e^{8 x} cos (3 x) - (- \frac{8}{3} \cdot \int e^{8 x} cos (3 x) d x))

Isolate

\int e^{8 x} cos (3 x) d x

= \frac{3 e ^{8 x} sin ( 3 x )}{73} + \frac{8 e ^{8 x} cos ( 3 x )}{73}

Add a constant to the solution

= \frac{3 e ^{8 x} sin ( 3 x )}{73} + \frac{8 e ^{8 x} cos ( 3 x )}{73} + C

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\frac{3 ( s + 1 ) \cdot e ^{- 2 s}}{s ( s + 1 ) ( 2 s + 1 )}

\frac{2 x + 1}{2 x - 1}

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\int \frac{1}{( x ^{2} + r ^{2} ) ^{\frac{3}{2}}} d x

What is the integral of+e^{8x}cos(3x) ?
The integral of+e^{8x}cos(3x) is (3e^{8x}sin(3x))/(73)+(8e^{8x}cos(3x))/(73)+C