What is the solution for (dy}{dx}=-\frac{2x)/y ?

The solution for (dy}{dx}=-\frac{2x)/y is y=sqrt(-2x^2+c_{1)},y=-sqrt(-2x^2+c_{1)}

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(dy}{dx}=-\frac{2x)/y

\frac{d y}{d x} = - \frac{2 x}{y}

y = - 2 x^{2} + c_{1}, y = - - 2 x^{2} + c_{1}

Solution steps

\frac{d y}{d x} = - \frac{2 x}{y}

Solve separable ODE:

y = - 2 x^{2} + c_{1}, y = - - 2 x^{2} + c_{1}

y = - 2 x^{2} + c_{1}, y = - - 2 x^{2} + c_{1}

(x + 1) (4 x^{2} - 4 x - 8)

\frac{\partial}{\partial x} (x^{3} y - x y^{3})

(- 12 x y^{2} - 12 y) + (- 12 x^{2} y - 12 x) y^{^{'}} = 0

\int e^{- 4 x} d x

\int \frac{( x ^{10} )}{x ^{2} + x - 2} d x

What is the solution for (dy}{dx}=-\frac{2x)/y ?
The solution for (dy}{dx}=-\frac{2x)/y is y=sqrt(-2x^2+c_{1)},y=-sqrt(-2x^2+c_{1)}