What is the tangent of f(x)= 4/x ,\at x=3 ?

The tangent of f(x)= 4/x ,\at x=3 is y=-4/9 x+8/3

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tangent of f(x)= 4/x ,\at x=3

tangent of

f (x) = \frac{4}{x}, at x = 3

y = - \frac{4}{9} x + \frac{8}{3}

Solution steps

Find the tangent point:

(3, \frac{4}{3})

Find the slope of

f (x) = \frac{4}{x} : \frac{df ( x )}{d x} = - \frac{4}{x ^{2}}

Compute the slope of

f (x) = \frac{4}{x}

x = 3 : m = - \frac{4}{9}

Find the line with slope m=

- \frac{4}{9}

and passing through

(3, \frac{4}{3}) : y = - \frac{4}{9} x + \frac{8}{3}

y = - \frac{4}{9} x + \frac{8}{3}

\frac{1}{4 s ^{2} + 1}

x \to 0 lim (x^{2} cos (\frac{2}{x}))

x \to - 4 lim (∣ x + 4 ∣)

\frac{2 x}{( x + 1 )}

\int 9 x^{3} e^{3 x} d x

What is the tangent of f(x)= 4/x ,\at x=3 ?
The tangent of f(x)= 4/x ,\at x=3 is y=-4/9 x+8/3