What is (\partial)/(\partial x)((10x)/(36+x^2+y^2)) ?

The answer to (\partial)/(\partial x)((10x)/(36+x^2+y^2)) is (10(-x^2+y^2+36))/((36+x^2+y^2)^2)

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(\partial)/(\partial x)((10x)/(36+x^2+y^2))

\frac{\partial}{\partial x} (\frac{10 x}{36 + x ^{2} + y ^{2}})

\frac{10 ( - x ^{2} + y ^{2} + 36 )}{( 36 + x ^{2} + y ^{2} ) ^{2}}

Solution steps

\frac{\partial}{\partial x} (\frac{10 x}{36 + x ^{2} + y ^{2}})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 10 \frac{\partial}{\partial x} (\frac{x}{36 + x ^{2} + y ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 10 \cdot \frac{\frac{\partial}{\partial x} ( x ) ( 36 + x ^{2} + y ^{2} ) - \frac{\partial}{\partial x} ( 36 + x ^{2} + y ^{2} ) x}{( 36 + x ^{2} + y ^{2} ) ^{2}}

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (36 + x^{2} + y^{2}) = 2 x

= 10 \cdot \frac{1 \cdot ( 36 + x ^{2} + y ^{2} ) - 2 xx}{( 36 + x ^{2} + y ^{2} ) ^{2}}

Simplify

10 \cdot \frac{1 \cdot ( 36 + x ^{2} + y ^{2} ) - 2 xx}{( 36 + x ^{2} + y ^{2} ) ^{2}} : \frac{10 ( - x ^{2} + y ^{2} + 36 )}{( 36 + x ^{2} + y ^{2} ) ^{2}}

= \frac{10 ( - x ^{2} + y ^{2} + 36 )}{( 36 + x ^{2} + y ^{2} ) ^{2}}

\int (x^{2} - 4 x) e^{2 x} d x

n = 1 \sum \infty \frac{1 0 ^{n}}{n ^{n}}

4 x^{4}

y \cdot e^{y} d x + (1 + x \cdot e^{y}) d y = 0, y (5) = 0, y = y

f (t) = 8 t - 9 t^{2}

What is (\partial)/(\partial x)((10x)/(36+x^2+y^2)) ?
The answer to (\partial)/(\partial x)((10x)/(36+x^2+y^2)) is (10(-x^2+y^2+36))/((36+x^2+y^2)^2)