What is laplacetransform sin(6(t-(5pi)/6)) ?

The answer to laplacetransform sin(6(t-(5pi)/6)) is -6/(s^2+36)

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laplacetransform sin(6(t-(5pi)/6))

laplace transform

sin (6 (t - \frac{5 π}{6}))

- \frac{6}{s ^{2} + 36}

Solution steps

L {sin (6 (t - \frac{5 π}{6}))}

Use Laplace Transform table:

L {sin (a t + b)} = \frac{s \cdot sin ( b ) + a \cdot cos ( b )}{s ^{2} + a ^{2}}

L {sin (6 (t - \frac{5 π}{6}))} = \frac{s sin ( - 5 π ) + 6 cos ( - 5 π )}{s ^{2} + 6 ^{2}}

= \frac{s sin ( - 5 π ) + 6 cos ( - 5 π )}{s ^{2} + 6 ^{2}}

= - \frac{6}{s ^{2} + 36}

\frac{1}{s ( 1 + s )}

y = x, y = \frac{x}{3}, y = 2

\int_{0}^{2} x^{2} 1 + x^{3} d x

\frac{d}{d x} (\frac{2}{1 + 4 x ^{2}})

\int \frac{x ^{2}}{36 + x ^{2}} d x

What is laplacetransform sin(6(t-(5pi)/6)) ?
The answer to laplacetransform sin(6(t-(5pi)/6)) is -6/(s^2+36)