What is the derivative of (x^3/2-3/(x^2)) ?

The derivative of (x^3/2-3/(x^2)) is (3x^2)/2+6/(x^3)

What is the first derivative of (x^3/2-3/(x^2)) ?

The first derivative of (x^3/2-3/(x^2)) is (3x^2)/2+6/(x^3)

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\frac{d}{d x} (\frac{x ^{3}}{2} - \frac{3}{x ^{2}})

\frac{3 x ^{2}}{2} + \frac{6}{x ^{3}}

Solution steps

\frac{d}{d x} (\frac{x ^{3}}{2} - \frac{3}{x ^{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{3}}{2}) - \frac{d}{d x} (\frac{3}{x ^{2}})

\frac{d}{d x} (\frac{x ^{3}}{2}) = \frac{3 x ^{2}}{2}

\frac{d}{d x} (\frac{3}{x ^{2}}) = - \frac{6}{x ^{3}}

= \frac{3 x ^{2}}{2} - (- \frac{6}{x ^{3}})

Simplify

= \frac{3 x ^{2}}{2} + \frac{6}{x ^{3}}

y^{^{''}} - 7 y^{^{'}} + 10 y = - 2 cos (2 t)

f (x) = 4 x - 1

\frac{d y}{d x} = 8 e^{x - y}

\int 3 v (v^{2} + 4)^{2} d v

\int x^{2} 5^{x} d x

What is the derivative of (x^3/2-3/(x^2)) ?
The derivative of (x^3/2-3/(x^2)) is (3x^2)/2+6/(x^3)
What is the first derivative of (x^3/2-3/(x^2)) ?
The first derivative of (x^3/2-3/(x^2)) is (3x^2)/2+6/(x^3)