What is the sum from n=1 to infinity of ((n+6))/2 ?

The sum from n=1 to infinity of ((n+6))/2 is diverges

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sum from n=1 to infinity of ((n+6))/2

n = 1 \sum \infty \frac{( n + 6 )}{2}

diverges

Solution steps

n = 1 \sum \infty \frac{n + 6}{2}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= \frac{1}{2} \cdot n = 1 \sum \infty n + 6

Apply Series Divergence Test:

diverges

= \frac{1}{2} diverges

= diverges

\frac{d ^{2}}{d x ^{2}} (\frac{x}{x ^{2} + 1})

2 x, \frac{x}{2}

\int \frac{x ^{2}}{( 1 - x ^{3} ) ^{7}} d x

x \to 0 lim (x^{5} cos (\frac{1}{x}))

cos^{2} (6 t)

What is the sum from n=1 to infinity of ((n+6))/2 ?
The sum from n=1 to infinity of ((n+6))/2 is diverges