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Popular >

integral of 1-t^2

Solution

\int 1 - t^{2} d t

Solution

t - \frac{t ^{3}}{3} + C

Solution steps

\int 1 - t^{2} d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 1 d t - \int t^{2} d t

\int 1 d t = t

\int t^{2} d t = \frac{t ^{3}}{3}

= t - \frac{t ^{3}}{3}

Add a constant to the solution

= t - \frac{t ^{3}}{3} + C

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Frequently Asked Questions (FAQ)

What is the integral of 1-t^2 ?
The integral of 1-t^2 is t-(t^3)/3+C