What is area y=\sqrt[3]{x},y= 1/x ?

The answer to area y=\sqrt[3]{x},y= 1/x is 3/(2^{2/3)}-3/4-ln(2)

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area y=\sqrt[3]{x},y= 1/x

area

\frac{3}{2 ^{\frac{2}{3}}} - \frac{3}{4} - ln (2)

Decimal Notation

0.44673 \dots

Solution steps

Apply the area formula:

Solve

The area is:

= \frac{3}{2 ^{\frac{2}{3}}} - \frac{3}{4} - ln (2)

f (x) = 2 - 6 x

\int ln (2 y) d y

y = (arctan (6 x))^{2}

\frac{\partial}{\partial x} (cos (12 x) sin (4 y))

\frac{( - 3 )}{s ( s - 3 )}

What is area y=\sqrt[3]{x},y= 1/x ?
The answer to area y=\sqrt[3]{x},y= 1/x is 3/(2^{2/3)}-3/4-ln(2)