What is the sum from n=0 to infinity of (7/4)^n ?

The sum from n=0 to infinity of (7/4)^n is diverges

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sum from n=0 to infinity of (7/4)^n

n = 0 \sum \infty (\frac{7}{4})^{n}

diverges

Solution steps

n = 0 \sum \infty (\frac{7}{4})^{n}

Apply Series Geometric Test:

diverges

= diverges

x \to \infty + lim (\frac{1}{5 x})

f (x) = 3 x + 40, at x = 3

\int (\frac{3 e ^{- x} + 2 e ^{3 x}}{e ^{2 x}}) d x

y^{^{'}} = \frac{t ( t ^{2} + 1 )}{4 y ^{3}}

\frac{\partial}{\partial x} (x y - x y)

What is the sum from n=0 to infinity of (7/4)^n ?
The sum from n=0 to infinity of (7/4)^n is diverges