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Popular >

derivative of f(x)=e-x^e+e^{41}-ln(2)

Solution

derivative of

f (x) = e - x^{e} + e^{41} - ln (2)

Solution

- e x^{e - 1}

Solution steps

\frac{d}{d x} (e - x^{e} + e^{41} - ln (2))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d e}{d x} - \frac{d}{d x} (x^{e}) + \frac{d}{d x} (e^{41}) - \frac{d}{d x} (ln (2))

\frac{d e}{d x} = 0

\frac{d}{d x} (x^{e}) = e x^{e - 1}

\frac{d}{d x} (e^{41}) = 0

\frac{d}{d x} (ln (2)) = 0

= 0 - e x^{e - 1} + 0 - 0

Simplify

= - e x^{e - 1}

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\frac{\partial}{\partial y} (\frac{x ^{2}}{y ^{2} + 1})

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Frequently Asked Questions (FAQ)

What is the derivative of f(x)=e-x^e+e^{41}-ln(2) ?
The derivative of f(x)=e-x^e+e^{41}-ln(2) is -ex^{e-1}
What is the first derivative of f(x)=e-x^e+e^{41}-ln(2) ?
The first derivative of f(x)=e-x^e+e^{41}-ln(2) is -ex^{e-1}