What is the tangent of y=xsqrt(x),(16,64) ?

The tangent of y=xsqrt(x),(16,64) is y=6x-32

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tangent of y=xsqrt(x),(16,64)

tangent of

y = x x, (16, 64)

y = 6 x - 32

Solution steps

Find the slope of

y = x x : \frac{d y}{d x} = \frac{3 x}{2}

Compute the slope of

y = x x

(16, 64) : m = 6

Find the line with slope m=

6

and passing through

(16, 64) : y = 6 x - 32

y = 6 x - 32

\int 36 - x^{2} d x

\frac{d ^{2}}{d x ^{2}} (\frac{6}{x})

\int \frac{1}{( 1 + x ^{3} )} d x

x \to 2 + lim (ln (x^{2} - 4))

y^{^{''}} - 2 y^{^{'}} + 4 y = 0, y (0) = 1, y^{^{'}} (0) = 2

What is the tangent of y=xsqrt(x),(16,64) ?
The tangent of y=xsqrt(x),(16,64) is y=6x-32