What is the d/(dt)(sqrt(t+1)) ?

The d/(dt)(sqrt(t+1)) is 1/(2sqrt(t+1))

What is the first d/(dt)(sqrt(t+1)) ?

The first d/(dt)(sqrt(t+1)) is 1/(2sqrt(t+1))

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\frac{d}{d t} (t + 1)

\frac{1}{2 t + 1}

Solution steps

\frac{d}{d t} (t + 1)

Apply the chain rule:

\frac{1}{2 t + 1} \frac{d}{d t} (t + 1)

= \frac{1}{2 t + 1} \frac{d}{d t} (t + 1)

\frac{d}{d t} (t + 1) = 1

= \frac{1}{2 t + 1} \cdot 1

Simplify

= \frac{1}{2 t + 1}

(- 4.3) (3.1)

\frac{d}{d x} (x (3 x + 1))

\frac{\partial}{\partial x} (arcsec (- x))

\frac{\partial}{\partial y} (y cos (x - y))

What is the d/(dt)(sqrt(t+1)) ?
The d/(dt)(sqrt(t+1)) is 1/(2sqrt(t+1))
What is the first d/(dt)(sqrt(t+1)) ?
The first d/(dt)(sqrt(t+1)) is 1/(2sqrt(t+1))