What is the integral from 0 to 0.6 of (150x) ?

The integral from 0 to 0.6 of (150x) is 27

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 0.6 of (150x)

\int_{0}^{0.6} (150 x) d x

27

Solution steps

\int_{0}^{0.6} 150 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 150 \cdot \int_{0}^{0.6} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{0.6}

= 150 [\frac{x ^{2}}{2}]_{0}^{0.6}

Simplify

= 150 [0.5 x^{2}]_{0}^{0.6}

Compute the boundaries:

0.18

= 150 \cdot 0.18

Simplify

= 27

\frac{d}{d x} (\frac{4}{( x + 2 ) ^{2}})

\int \frac{x ^{4} + 9 x ^{2} + x + 2}{x ^{2} + 9} d x

x \to - 2 lim (\frac{2 - x}{2 + x})

2 x^{2} (3 x^{4} - 2)

\frac{\partial}{\partial x} (6 x sin (x^{2} y))

What is the integral from 0 to 0.6 of (150x) ?
The integral from 0 to 0.6 of (150x) is 27