What is the derivative of cot(e^x) ?

The derivative of cot(e^x) is -csc^2(e^x)e^x

What is the first derivative of cot(e^x) ?

The first derivative of cot(e^x) is -csc^2(e^x)e^x

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\frac{d}{d x} (cot (e^{x}))

- csc^{2} (e^{x}) e^{x}

Solution steps

\frac{d}{d x} (cot (e^{x}))

Apply the chain rule:

- csc^{2} (e^{x}) \frac{d}{d x} (e^{x})

= - csc^{2} (e^{x}) \frac{d}{d x} (e^{x})

\frac{d}{d x} (e^{x}) = e^{x}

= - csc^{2} (e^{x}) e^{x}

\int \frac{x + 4}{x ^{2} + 6 x + 18} d x

n = 3 \sum \infty (\frac{4}{10})^{n}

\frac{d}{d x} (4 (5 - 8 x)^{5})

\frac{\partial}{\partial x} (x^{2} y + 10 x y)

y = ln (8) x^{2}

What is the derivative of cot(e^x) ?
The derivative of cot(e^x) is -csc^2(e^x)e^x
What is the first derivative of cot(e^x) ?
The first derivative of cot(e^x) is -csc^2(e^x)e^x