What is the derivative of Ae^x+Be^{-x} ?

The derivative of Ae^x+Be^{-x} is Ae^x-Be^{-x}

What is the first derivative of Ae^x+Be^{-x} ?

The first derivative of Ae^x+Be^{-x} is Ae^x-Be^{-x}

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\frac{d}{d x} (A e^{x} + B e^{- x})

A e^{x} - B e^{- x}

Solution steps

\frac{d}{d x} (A e^{x} + B e^{- x})

Treat

A, B

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (A e^{x}) + \frac{d}{d x} (B e^{- x})

\frac{d}{d x} (A e^{x}) = A e^{x}

\frac{d}{d x} (B e^{- x}) = - B e^{- x}

= A e^{x} - B e^{- x}

x y^{^{'}} = ((1 - x) y + x^{2} + x^{3}), y (3) = 2

x \to 3 - lim (\frac{x}{∣ x ∣})

\frac{\partial}{\partial x} (2 y^{7} + 7 y^{9} x^{6})

\int 2 x (x + 1) d x

x \to 2 lim (x^{3} + 8)

What is the derivative of Ae^x+Be^{-x} ?
The derivative of Ae^x+Be^{-x} is Ae^x-Be^{-x}
What is the first derivative of Ae^x+Be^{-x} ?
The first derivative of Ae^x+Be^{-x} is Ae^x-Be^{-x}