What is area y=-11x+3,y=-x,[0,0.3] ?

The answer to area y=-11x+3,y=-x,[0,0.3] is 0.45

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area y=-11x+3,y=-x,[0,0.3]

area

y = - 11 x + 3, y = - x, [0, 0.3]

0.45

Solution steps

Apply the area formula:

\int_{0}^{0.3} ∣ - 10 x + 3 ∣ d x

Solve

\int_{0}^{0.3} ∣ - 10 x + 3 ∣ d x : 0.45

The area is:

= 0.45

\frac{3}{4 x}

\int sin^{2} (3 θ) d θ

\int - \frac{3}{x} + 3 e^{x} d x

\int (\frac{sin ( x )}{2 e ^{x}}) d x

y^{^{'}} = 5 y^{2} + x y^{2}

What is area y=-11x+3,y=-x,[0,0.3] ?
The answer to area y=-11x+3,y=-x,[0,0.3] is 0.45