What is the derivative of x^2+4x+8 ?

The derivative of x^2+4x+8 is 2x+4

What is the first derivative of x^2+4x+8 ?

The first derivative of x^2+4x+8 is 2x+4

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derivative of

x^{2} + 4 x + 8

2 x + 4

Solution steps

\frac{d}{d x} (x^{2} + 4 x + 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (4 x) + \frac{d}{d x} (8)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (8) = 0

= 2 x + 4 + 0

Simplify

= 2 x + 4

\frac{\partial}{\partial x} (x^{2} + yz)

x \frac{d y}{d x} + \frac{y ^{2}}{x} = y

\frac{\partial}{\partial y} (3 x^{2} y^{2} - 3)

\int_{1}^{7} 3 x^{2} + \frac{1}{12 x ^{2}} d x

\frac{d}{d x} (ln^{2} (1 + x))

What is the derivative of x^2+4x+8 ?
The derivative of x^2+4x+8 is 2x+4
What is the first derivative of x^2+4x+8 ?
The first derivative of x^2+4x+8 is 2x+4