What is the tangent of f(x)=(6x+5)/(x-1),\at x=2 ?

The tangent of f(x)=(6x+5)/(x-1),\at x=2 is y=-11x+39

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tangent of f(x)=(6x+5)/(x-1),\at x=2

tangent of

f (x) = \frac{6 x + 5}{x - 1}, at x = 2

y = - 11 x + 39

Solution steps

Find the tangent point:

(2, 17)

Find the slope of

f (x) = \frac{6 x + 5}{x - 1} : \frac{df ( x )}{d x} = - \frac{11}{( x - 1 ) ^{2}}

Compute the slope of

f (x) = \frac{6 x + 5}{x - 1}

x = 2 : m = - 11

Find the line with slope m=

- 11

and passing through

(2, 17) : y = - 11 x + 39

y = - 11 x + 39

t \to 2 lim (\frac{t - 2}{t ^{2} - 4})

\int 19 tan^{2} (x) sec^{3} (x) d x

\frac{\partial}{\partial x} (4 x^{3} + 2 x y + 1)

\int x^{2} csc^{2} (x^{3}) d x

x \to \infty lim (\frac{an + 1}{an})

What is the tangent of f(x)=(6x+5)/(x-1),\at x=2 ?
The tangent of f(x)=(6x+5)/(x-1),\at x=2 is y=-11x+39