What is the derivative of (x^2-3^3) ?

The derivative of (x^2-3^3) is 6x(x^2-3)^2

What is the first derivative of (x^2-3^3) ?

The first derivative of (x^2-3^3) is 6x(x^2-3)^2

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\frac{d}{d x} ((x^{2} - 3)^{3})

6 x (x^{2} - 3)^{2}

Solution steps

\frac{d}{d x} ((x^{2} - 3)^{3})

Apply the chain rule:

3 (x^{2} - 3)^{2} \frac{d}{d x} (x^{2} - 3)

= 3 (x^{2} - 3)^{2} \frac{d}{d x} (x^{2} - 3)

\frac{d}{d x} (x^{2} - 3) = 2 x

= 3 (x^{2} - 3)^{2} \cdot 2 x

Simplify

= 6 x (x^{2} - 3)^{2}

f (x) = (x - 2) (5 x + 3)

f (x) = \frac{1}{x}, at x = - 1

\int_{0}^{1} \frac{( x ^{4} + 4 )}{x} d x

x \to 0 + lim ((x)^{x})

x \to 3 lim (- 9)

What is the derivative of (x^2-3^3) ?
The derivative of (x^2-3^3) is 6x(x^2-3)^2
What is the first derivative of (x^2-3^3) ?
The first derivative of (x^2-3^3) is 6x(x^2-3)^2