What is the tangent of f(x)=x^2-6,(-4,10) ?

The tangent of f(x)=x^2-6,(-4,10) is y=-8x-22

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tangent of f(x)=x^2-6,(-4,10)

tangent of

f (x) = x^{2} - 6, (- 4, 10)

y = - 8 x - 22

Solution steps

Find the slope of

f (x) = x^{2} - 6 : \frac{df ( x )}{d x} = 2 x

Compute the slope of

f (x) = x^{2} - 6

(- 4, 10) : m = - 8

Find the line with slope m=

- 8

and passing through

(- 4, 10) : y = - 8 x - 22

y = - 8 x - 22

\int (x^{- 3}) d x

\frac{d y}{d t} = t^{2} e^{- 4 t} - 4 y

7 x y^{3} + 5 x y = 12, at x = 1

(2 x + 3) + (2 y - 2) y^{^{'}} = 0

\int x^{2} x - 3 d x

What is the tangent of f(x)=x^2-6,(-4,10) ?
The tangent of f(x)=x^2-6,(-4,10) is y=-8x-22