What is the limit as x approaches 8 of (1+\sqrt[3]{x})(2-6x^2+x^2) ?

The limit as x approaches 8 of (1+\sqrt[3]{x})(2-6x^2+x^2) is -954

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limit as x approaches 8 of (1+\sqrt[3]{x})(2-6x^2+x^2)

x \to 8 lim ((1 + 3 x) (2 - 6 x^{2} + x^{2}))

- 954

Solution steps

x \to 8 lim ((1 + 3 x) (2 - 6 x^{2} + x^{2}))

Plug in the value

x = 8

= (1 + 38) (2 - 6 \cdot 8^{2} + 8^{2})

Simplify

(1 + 38) (2 - 6 \cdot 8^{2} + 8^{2}) : - 954

= - 954

\int \frac{( x ^{2} + 5 x + 4 )}{x ^{2} - 2 x + 1} d x

y = x, y = 5 x - x^{2}

\frac{d}{d x} (- 2 + 2 (- 1)^{x})

\frac{- 2 n x ^{n - 1}}{( 1 + x ^{n} ) ^{2}}

\frac{\partial}{\partial y} (5 x e^{x^{2} + y^{2}})

What is the limit as x approaches 8 of (1+\sqrt[3]{x})(2-6x^2+x^2) ?
The limit as x approaches 8 of (1+\sqrt[3]{x})(2-6x^2+x^2) is -954