What is the integral of (sqrt(n)+3)^3 ?

The integral of (sqrt(n)+3)^3 is 2/5 n^{5/2}+(9n^2)/2+18n^{3/2}+27n+C

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integral of (sqrt(n)+3)^3

\int (n + 3)^{3} d n

\frac{2}{5} n^{\frac{5}{2}} + \frac{9 n ^{2}}{2} + 18 n^{\frac{3}{2}} + 27 n + C

Solution steps

\int (n + 3)^{3} d n

Expand

(n + 3)^{3} : n^{\frac{3}{2}} + 9 n + 27 n + 27

= \int n^{\frac{3}{2}} + 9 n + 27 n + 27 d n

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int n^{\frac{3}{2}} d n + \int 9 n d n + \int 27 n d n + \int 27 d n

\int n^{\frac{3}{2}} d n = \frac{2}{5} n^{\frac{5}{2}}

\int 9 n d n = \frac{9 n ^{2}}{2}

\int 27 n d n = 18 n^{\frac{3}{2}}

\int 27 d n = 27 n

= \frac{2}{5} n^{\frac{5}{2}} + \frac{9 n ^{2}}{2} + 18 n^{\frac{3}{2}} + 27 n

Add a constant to the solution

= \frac{2}{5} n^{\frac{5}{2}} + \frac{9 n ^{2}}{2} + 18 n^{\frac{3}{2}} + 27 n + C

\int ln^{2} (x - 9) d x

ln (x^{2}) - \frac{1}{x ^{2}} - 5

y^{3} = 126 - x^{3}, at x = 5

\frac{d}{d x} (2^{3} e^{2})

\int \frac{x ^{2}}{a x ^{2} - b} d x

What is the integral of (sqrt(n)+3)^3 ?
The integral of (sqrt(n)+3)^3 is 2/5 n^{5/2}+(9n^2)/2+18n^{3/2}+27n+C