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Popular >

y^'+2y=4,y(0)=4

Solution

y^{^{'}} + 2 y = 4, y (0) = 4

Solution

y = 2 + \frac{2}{e ^{2 t}}

Solution steps

y^{'} (t) + 2 y = 4

Solve linear ODE:

y = 2 + \frac{2}{e ^{2 t}}

y = 2 + \frac{2}{e ^{2 t}}

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Frequently Asked Questions (FAQ)

What is the solution for y^'+2y=4,y(0)=4 ?
The solution for y^'+2y=4,y(0)=4 is y=2+2/(e^{2t)}